Chlorine atom, in its third excited state, reacts with fluorine to form a compound $X$. The formula and…
Chlorine atom, in its third excited state, reacts with fluorine to form a compound $X$. The formula and shape of $X$ are :
$\mathrm{ClF}_5$, pentagonal
$\mathrm{ClF}_4$, tetrahedral
$\mathrm{ClF}_4$ pentagonal bipyramidal
$\mathrm{ClF}_7$, pentagonal bipyramidal
Solution
From the diagram, it is clear that chlorine has 7 unpaired orbitals each of which can form a bond with fluorine. Hence, hybridization is \(\mathrm{sp}^3 \mathrm{~d}^3\) and shape is pentagonal bipyramidal.
