Chiral complex from the following is : Here en = ethylene diamine

Chiral complex from the following is :
Here en = ethylene diamine
  1. cis -PtCl2(en)22+
  2. trans -PtCl2(en)22+
  3. cis -PtCl2NH32
  4. trans -CoNH34Cl2+

Solution

Here en = ethylene diamine 

 

 [PtCl2(en)2]2+ forms cis and trans-isomers. Only the cis-isomers has no element of symmetry. So it is optically active. Trans - [PtCl2(en)2]2+ form is optically inactive. Square planar complexes doesn't exhibit optical isomerism.

Asked in: JEE Main 2023 (29 Jan Shift 1)

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