\(\underset{a}{\mathrm{CH}_{3}}-\underset{b}{\mathrm{CH}_{2}}-\underset{c}{\mathrm{CH}_{2}}-\underset{d}{\mathrm{CH}_{2}}-\mathrm{F}\)
Arrange the hydrogens \(a, b, c, d\), in decreasing order of their reactivities towards chlorination:
\(a>b>c>d\)
\(b>c>d>a\)
\(b>c>a>d\)
\(c>b>a>d\)
Solution
Among all of them hydrogen '\(\mathrm{b}\)' will be most leachive towards chlorination as it is \(2^{\circ}\) hydrogen and it will get less electronegativity of fluorine atom and 'd' will be least stable as it is adjacent to the fluorine atom and does not have \(3^{\circ}-2^{\circ}\) hydrogen.