CH 3 CO CH 2 CH 2 CH 2 COOH → NaBH 4 → H 2 O A The compound A would be:

{CH}_{3} CO {CH}_{2} {CH}_{2} {CH}_{2} COOH \overset{{NaBH}_{4}}{\to} \overset{H_{2} O}{\to} (A)

The compound

(A)

would be:

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more ALDEHYDES, KETONES AND CARBOXYLIC ACIDS questions on Aicharya