Carbon monoxide is carried around a closed cycle abc in which bc isothermal process as shown in figure. The gas absorbs $7000 \mathrm{~J}$ of heat as its temperture increases from $300\mathrm{K}$ to $1000 \mathrm{~K}$ in going from a to $\mathrm{b}$. quantity of heat rejected by the during the process ca is

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Aicharya · Accepted Answer

For path ab : $(\Delta U)_{a b}=7000 \mathrm{~J}$
By using $\Delta U=\mu C_{V} \Delta T$
$7000=\mu \times \frac{5}{2} R \times 700 \Rightarrow \mu=0.48$
For path ca :
$(\Delta Q)_{c a}=(\Delta U)_{c a}+(\Delta W)_{c a}$
$\because(\Delta U)_{a b}+(\Delta U)_{b c}+(\Delta U)_{c a}=0$
$\because 7000+0+(\Delta U)_{c a}=0 \Rightarrow(\Delta U)_{c a}=-7000 J \ldots$ (ii)
Also $(\Delta W)_{c a}=P_{1}\left(V_{1}-V_{2}ight)=\mu R\left(T_{1}-T_{2}ight)$
$=0.48 \times 8.31 \times(300-1000)=-2792.16 \mathrm{~J}$
On solving equations (i), (ii) and (iii)
$(\Delta Q)_{c a}=-7000-2792.16=-9792.16 J \approx-9800 \mathrm{~J}$ ,

Carbon monoxide is carried around a closed cycle abc in which bc isothermal process as shown in figure. The…

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