Carbon is present in highest oxidation number in
- $\mathrm{CO}_{3}^{2-}$
- $\cdot \mathrm{CaC}_{2}$
- $\mathrm{CO}$
- $\mathrm{C}_{2} \mathrm{O}_{4}^{2-}$
Solution
Here, highest oxidation number $=+4$ in $\mathrm{CO}_{3}^{2-}$.Asked in: MHT CET 2020 (20 Oct Shift 1)