$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CONHCH}_3$ can be converted into $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2…
$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CONHCH}_3$ can be converted into $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{NHCH}_3$ by
$\mathrm{NaBH}_4$
$\mathrm{H}_2-\mathrm{Pd} / \mathrm{C}$
$\mathrm{LiAl}_4$
$\mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}$.
Solution
$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CONHCH}_3 \stackrel{\mathrm{Zn}-\mathrm{Hg}}{\mathrm{HCl}} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{NHCH}_3$
This reaction is known as Clemmenson reduction.