$\mathrm{R}-\mathrm{CH}_{2}-\mathrm{CH}_{2} \mathrm{OH}$ can be converted in $\mathrm{R}-\mathrm{CH}_{2}…

$\mathrm{R}-\mathrm{CH}_{2}-\mathrm{CH}_{2} \mathrm{OH}$ can be converted in $\mathrm{R}-\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH} .$ The correct sequence of reagents is
  1. $\mathrm{PBr}_{3}, \mathrm{KCN}, \mathrm{H}^{+}$
  2. $\mathrm{PBr}_{3}, \mathrm{KCN}, \mathrm{H}_{2}$
  3. $\mathrm{KCN}, \mathrm{H}^{+}$
  4. $\mathrm{HCN}, \mathrm{PBr}_{3}, \mathrm{H}^{+}$

Solution

$\mathrm{RCH}_{2} \mathrm{CH}_{2} \mathrm{OH} \stackrel{\mathrm{PBr}_{3}}{\longrightarrow} \mathrm{RCH}_{2} \mathrm{CH}_{2} \mathrm{Br} \stackrel{\mathrm{KCN}}{\longrightarrow} \mathrm{RCH}_{2} \mathrm{CH}_{2} \mathrm{CN} \stackrel{\mathrm{H}_{2} \mathrm{O} / \mathrm{H}^{+}}{\longrightarrow} \mathrm{RCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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