Calomel $\left(\mathrm{Hg}_2 \mathrm{Cl}_2\right)$ on reaction with ammonium hydroxide gives

Calomel $\left(\mathrm{Hg}_2 \mathrm{Cl}_2\right)$ on reaction with ammonium hydroxide gives
  1. $\mathrm{HgNH}_2 \mathrm{Cl}$
  2. $\mathrm{NH}_2-\mathrm{Hg}-\mathrm{Hg}-\mathrm{Cl}$
  3. $\mathrm{Hg}_2 \mathrm{O}$
  4. $\mathrm{HgO}$

Solution

$\mathrm{Hg} \mathrm{Cl}+2 \mathrm{NHOH} \longrightarrow \mathrm{Hg}+\mathrm{Hg}\left(\mathrm{NH}_2\right) \mathrm{Cl}+\mathrm{NH}_4 \mathrm{Cl}+2 \mathrm{H}_2 \mathrm{O}$

Asked in: JEE Main 2005

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