Calculated magnetic moment value for $\mathrm{Fe}^{2+}$ ion in $\mathrm{BM}$ is

Calculated magnetic moment value for $\mathrm{Fe}^{2+}$ ion in $\mathrm{BM}$ is
  1. $3.87$
  2. $4.90$
  3. $2.84$
  4. $1.73$

Solution

$\mathrm{Fe}^{2+}\left(\mathrm{d}^6\right):$ Unpaired electrons $(\mathrm{n})=4$ $\therefore \quad \mu_{\text {s.o. }}=\sqrt{4(4+2)}=2 \sqrt{6}=4.89 \simeq 4.90 \mathrm{BM}$

Asked in: AP EAMCET 2022 (05 Jul Shift 2)

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