Calculate wave length for emission of a photon having wave number $11516 \mathrm{~cm}^{-1}$.
Calculate wave length for emission of a photon having wave number $11516 \mathrm{~cm}^{-1}$.
- 216 nm
- 434 nm
- 868 nm
- 642 nm
Solution
$\begin{aligned} & \text {Wavelength }(\lambda)=\frac{1}{\bar{v}}=\frac{1}{11516 \mathrm{~cm}^{-1}} \\ & =8.68 \times 10^{-5} \mathrm{~cm} \\ & =868 \mathrm{~nm} \quad\left(\because 1 \mathrm{~nm}=10^{-7} \mathrm{~cm}\right)\end{aligned}$
Asked in: MHT CET 2024 (04 May Shift 1)
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