Calculate vapour pressure of a solution containing mixture of 2 moles of volatile liquid A and 3 moles of…

Calculate vapour pressure of a solution containing mixture of 2 moles of volatile liquid A and 3 moles of volatile liquid B at room temperature. $\left(\mathrm{P}_{\mathrm{A}}^{\circ}=420, \mathrm{P}_{\mathrm{B}}^{\circ}=610 \mathrm{~mm} \mathrm{Hg}\right)$
  1. 600 mm Hg
  2. 570 mm Hg
  3. 534 mm Hg
  4. 480 mm Hg

Solution

$\begin{aligned} & \mathrm{x}_1=\frac{\mathrm{n}_1}{\mathrm{n}_1+\mathrm{n}_2}=\frac{2}{2+3}=0.4 \\ & \mathrm{x}_2=\frac{\mathrm{n}_1}{\mathrm{n}_1+\mathrm{n}_2}=\frac{3}{2+3}=0.6 \\ & \mathrm{P}_{\text {solution }}=\mathrm{P}_{\mathrm{A}}^0 \mathrm{x}_1+\mathrm{P}_{\mathrm{B}}^0 \mathrm{x}_2 \\ & =420 \times 0.4+610 \times 0.6 \\ & =168+366 \\ & =534 \mathrm{~mm} \mathrm{Hg} \end{aligned}$

Asked in: MHT CET 2024 (04 May Shift 1)

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