Calculate van't Hoff factor of 0.15 M solution of electrolyte if it freezes at -0.5 K. $\left[\mathrm{K}_{\mathrm{f}}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right]$

Question

Aicharya · Accepted Answer

$\begin{array}{ll} & \Delta \mathrm{T}_{\mathrm{f}}=\mathrm{T}_{\mathrm{f}}^0-\mathrm{T}_{\mathrm{f}}=0-(-0.5 \mathrm{~K})=0.5 \mathrm{~K} \ & \Delta \mathrm{~T}_{\mathrm{f}}=\mathrm{i} \mathrm{K}_{\mathrm{f}} \mathrm{m} \ 	herefore \quad & \mathrm{i}=\frac{\Delta \mathrm{T}}{\mathrm{K}_{\mathrm{f}} \mathrm{m}}=\frac{0.5 \mathrm{~K}}{1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1} 	imes 0.15 \mathrm{~mol} \mathrm{~kg}^{-1}}=1.79\end{array}$

Calculate van't Hoff factor of 0.15 M solution of electrolyte if it freezes at -0.5 K.…

Solution