Calculate the total volume occupied by all atoms in simple cubic unit cell if radius of atom is $3 \times…
Calculate the total volume occupied by all atoms in simple cubic unit cell if radius of atom is $3 \times 10^{-8} \mathrm{~cm}$ :
- $1.13 \times 10^{-22} \mathrm{~cm}^3$
- $2.25 \times 10^{-22} \mathrm{~cm}^3$
- $3.15 \times 10^{-22} \mathrm{~cm}^3$
- $4.37 \times 10^{-22} \mathrm{~cm}^3$
Solution
For simple cubic unit cell, $\mathrm{n}=1$
Total volume occupied by atoms in SCC
$\begin{aligned}
& =\mathrm{n} \times \frac{4}{3} \times \pi \mathrm{r}^3 \\
& =1 \times \frac{4}{3} \times \frac{22}{7} \times\left(3 \times 10^{-8}\right)^3=1.13 \times 10^{-22} \mathrm{~cm}^3
\end{aligned}$
Asked in: MHT CET 2024 (15 May Shift 1)
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