Calculate the time required for reactant to decrease the concentration from $100 \%$ to $20 \%$, if rate constant of first order reaction is 0.02303 hours $^{-1}$.

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{kt}=\ln \frac{\left[\mathrm{A}_0ight]}{\mathrm{A}} \ & 0.02303 	ext { hour }^{-1} 	imes \mathrm{t}=\ln \frac{100}{20} \ & \mathrm{t}=69.88 	ext { hour } \approx 70 	ext { hour }\end{aligned}$

Calculate the time required for reactant to decrease the concentration from $100 \%$ to $20 \%$, if rate…

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