Calculate the solubility product of sparingly soluble salt BA at $25^{\circ} \mathrm{C}$ if its solubility…

Calculate the solubility product of sparingly soluble salt BA at $25^{\circ} \mathrm{C}$ if its solubility is $7.2 \times 10^{-7} \mathrm{~mol} \mathrm{dm}^{-3}$ at same temperature.
  1. $4.810 \times 10^{-13}$
  2. $5.184 \times 10^{-13}$
  3. $6.454 \times 10^{-13}$
  4. $5.925 \times 10^{-13}$

Solution

$\begin{array}{ll} & \mathrm{BA}_{(\mathrm{s})} \rightleftharpoons \mathrm{B}_{(\mathrm{aq})}^{+}+\mathrm{A}_{(\mathrm{aq})}^{-} \\ & x=1, \mathrm{y}=1 \\ \quad & \mathrm{~K}_{\mathrm{sp}}=x^x \mathrm{y}^{\mathrm{y}} \mathrm{S}^{x+\mathrm{y}}=(1)^1(1)^1 \mathrm{~S}^{1+1}=\mathrm{S}^2 \\ \therefore \quad & \mathrm{~K}_{\mathrm{sp}}=\left(7.2 \times 10^{-7}\right)^2=5.184 \times 10^{-13}\end{array}$

Asked in: MHT CET 2024 (04 May Shift 2)

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