Calculate the solubility of gas in water at $1.2 \mathrm{~atm}$ and $25^{\circ} \mathrm{C}$ if Henry's law…

Calculate the solubility of gas in water at $1.2 \mathrm{~atm}$ and $25^{\circ} \mathrm{C}$ if Henry's law constant is $0.45 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~atm}^{-1}$ at $25^{\circ} \mathrm{C}$.
  1. $0.45 \mathrm{~mol} \mathrm{dm}^{-3}$
  2. $0.54 \mathrm{~mol} \mathrm{dm}^{-3}$
  3. $0.25 \mathrm{~mol} \mathrm{dm}^{-3}$
  4. $0.31 \mathrm{~mol} \mathrm{dm}^{-3}$

Solution

$\begin{aligned} & \text { Solubility }(\mathrm{s})=\mathrm{k} \times \mathrm{p} \\ & =0.45 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~atm}^{-1} \times 1.2 \mathrm{~atm} \\ & =0.54 \mathrm{~mol} \mathrm{dm}^{-3}\end{aligned}$

Asked in: MHT CET 2022 (05 Aug Shift 2)

Practice more Solutions questions on Aicharya