Calculate the solubility of gas in solvent at $25^{\circ} \mathrm{C}$ and 0.8 atm if Henry's law constant…

Calculate the solubility of gas in solvent at $25^{\circ} \mathrm{C}$ and 0.8 atm if Henry's law constant for solvent is $6.8 \times 10^{-4} \mathrm{~mol~} \mathrm{dm}^{-3} \mathrm{~atm}^{-1}$.
  1. $5.88 \times 10^{-4} \mathrm{M}$
  2. $6.12 \times 10^{-4} \mathrm{M}$
  3. $5.44 \times 10^{-4} \mathrm{M}$
  4. $6.48 \times 10^{-4} \mathrm{M}$

Solution

Using Henry's Law, the solubility $S$ of a gas is given by $S = K_H \times P_{\text{gas}}$, where $K_H = 6.8 \times 10^{-4}\,\text{mol}\,\text{dm}^{-3}\,\text{atm}^{-1}$ and $P_{\text{gas}} = 0.8\,\text{atm}$.

Substituting yields $S = (6.8 \times 10^{-4}) \times 0.8 = 5.44 \times 10^{-4}\,\text{mol}\,\text{dm}^{-3}$.

This corresponds to option C.

Asked in: MHT CET 2025 (05 May Shift 2)

Practice more Solutions questions on Aicharya