Calculate the solubility of a gas in water at $0.8 \mathrm{~atm}$ and $25^{\circ} \mathrm{C}$ [Henry's law…

Calculate the solubility of a gas in water at $0.8 \mathrm{~atm}$ and $25^{\circ} \mathrm{C}$ [Henry's law constant is $6.85 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~atm}^{-1}$ ]
  1. $5.48 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3}$
  2. $3.94 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3}$
  3. $6.858 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3}$
  4. $2.74 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3}$

Solution

$\begin{aligned} & S=P k \\ & =0.8 \times 6.85 \times 10^{-4} \\ & =5.48 \times 10^{-4} \mathrm{~mol} / \mathrm{dm}^{-3}\end{aligned}$

Asked in: MHT CET 2022 (10 Aug Shift 2)

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