Calculate the relative lowering of vapour pressure if the vapour pressure of benzene and vapour pressure of…

Calculate the relative lowering of vapour pressure if the vapour pressure of benzene and vapour pressure of solution of non-volatile solute in benzene are $640 \mathrm{mmHg}$ and $590 \mathrm{mmHg}$ respectively at same temperature.
  1. $0.078$
  2. $0.175$
  3. $0.061$
  4. $0.092$

Solution

Relative lowering of vapour pressure $\begin{aligned} & =\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}=\frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0} \\ & =\frac{640-590}{640}=0.078 \end{aligned}$

Asked in: MHT CET 2023 (14 May Shift 1)

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