Calculate the ratio of $\mathrm{pH}$ of a solution containing $1 \mathrm{~mol}$ of $\mathrm{NaCN}+1…

Calculate the ratio of $\mathrm{pH}$ of a solution containing $1 \mathrm{~mol}$ of $\mathrm{NaCN}+1 \mathrm{~mol}$ of $\mathrm{HNO}_{3}$ per liter and of other solution containing lmol NaCN + lmol of HCN per litre Given $: \mathrm{K}_{\mathrm{a}}$ of $\mathrm{HCN}$ is the order of $10^{-10}$.
  1. $1: 1$
  2. $2: 1$
  3. $1: 2$
  4. Data insufficient

Solution

$K_{a}$ of $H C N$ is the order of $10^{-10}$ so at this concentration, a of HCN will be negligible. \(\begin{array}{cccc} \mathrm{NaCN} & + & \mathrm{HNO}_3 & ightarrow & \mathrm{HCN} & + & \mathrm{NaNO}_3 \\ 1 & & 1 & & \\ 0 & & 0 & & 1 & & 1 \end{array}\) $[\mathrm{HCN}]=1 \mathrm{M}$ $\mathrm{pH}_{1}=\frac{1}{2} \mathrm{pK}_{\mathrm{a}}-\frac{1}{2} \log 1$ $\mathbf{p H}_{\mathbf{2}}=\mathbf{p} \mathbf{K}_{\mathbf{a}}$ $\frac{\mathrm{pH}_{1}}{\mathrm{p} \mathrm{H}_{2}}=\frac{1}{2}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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