Calculate the radius of first orbit of $\mathrm{Be}^{3+}$.
Calculate the radius of first orbit of $\mathrm{Be}^{3+}$.
- $13.23 \mathrm{pm}$
- $52.9 \mathrm{pm}$
- $17.63 \mathrm{pm}$
- $26.45 \mathrm{pm}$
Solution
$\begin{aligned} r_n & =\frac{n^2}{z} \times 0.53 Å \\ & =\frac{1}{4} \times 0.53 Å \\ & =\frac{1}{4} \times 0.53 Å \\ & =0.1325 Å \\ & =13.25 \mathrm{pm}\end{aligned}$
Asked in: MHT CET 2022 (10 Aug Shift 1)
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