Calculate the quantity of electricity required to liberate 0.1 mole of chlorine gas during electrolysis of…
- 9665 C
- 19300 C
- 14500 C
- 96500 C
Solution
1 mole of $\mathrm{Cl}_2$ is liberated with 2 moles of electrons. $\begin{aligned} & \therefore \quad 0.1 \text { mole of } \mathrm{Cl}_2 \text { will be liberated with } 0.2 \text { moles } \\ & \text { of electrons. } \end{aligned}$
Asked in: MHT CET 2024 (02 May Shift 2)