Calculate the PV type of work for the following reaction at 1 bar pressure. $\underset{(150…

Calculate the PV type of work for the following reaction at 1 bar pressure. $\underset{(150 \mathrm{~mL})}{\mathrm{C}_3 \mathrm{H}_{6(\mathrm{~g})}}+\underset{(150 \mathrm{~mL})}{\mathrm{HCl}_{(\mathrm{g})}} \longrightarrow \underset{(150 \mathrm{~mL})}{\mathrm{C}_3 \mathrm{H}_7 \mathrm{Cl}_{(\mathrm{g})}}$
  1. $5.2 J$
  2. $10.21 J$
  3. $15.00 J$
  4. $18.2 J$

Solution

$\begin{aligned} \mathrm{W} & =-\mathrm{P}_{\text {ext }} \Delta \mathrm{V}=-\mathrm{P}_{\text {ext }}\left(\mathrm{V}_2-\mathrm{V}_1\right) \\ \mathrm{V}_1 & =150+150=300 \mathrm{~mL}=0.3 \mathrm{dm}^3 \\ \mathrm{~V}_2 & =150 \mathrm{~mL}=0.15 \mathrm{dm}^3 \\ \mathrm{P}_{\text {ext }} & =1 \mathrm{bar} \\ \mathrm{W} & =-1(0.15-0.3) \\ & =0.15 \mathrm{dm}^3 \text { bar } \\ & =15.0 \mathrm{~J} \quad\left(\because 100 \mathrm{~J}=1 \mathrm{dm}^3 \text { bar }\right)\end{aligned}$

Asked in: MHT CET 2023 (14 May Shift 2)

Practice more Chemical Thermodynamics questions on Aicharya