Calculate the percentage of all the monochlorinated products obtained from the chlorination of 2 - methyl…

1. 15%, 45%, 20%, 25%
2. 14%, 35%, 23%, 28%
3. 12%, 30%, 22%, 29%
4. 17%, 36%, 20%, 23%

Solution

There are four different (A, B, C and D) monochloro products.
 

			Relative amount
(A)		(A) is obtained from the reaction of three equivalent $1^{\circ }$ H atoms.	3 x 1 = 3.0
(B)		(B) is obtained from the reaction of two equivalent $2^{\circ }$ H atoms.	2 x 3.8 = 7.6
(C)		(C) is obtained from the reaction of one equivalent $3^{\circ }$ H atoms.	1 x 5 = 5.0
(D)		(D) is obtained from the reaction of six equivalent $1^{\circ }$ H atoms.	6 x 1 = 6.0 Total = 21.6

Therefore, percentages of the A, B, C and D monochloro products are as follows :

$\left(\text{A}\right)=\frac{3}{21\text{.}6}\times 100=13\text{.}9\approx 14\text{\%}$

$\left(\text{B}\right)=\frac{7\text{.}6}{21\text{.}6}\times 100=35\text{.}18\approx 35\text{\%}$

$\left(\text{C}\right)=\frac{5\text{.}0}{21\text{.}6}\times 100=23\text{.}15\approx 23\text{\%}$

$\left(\text{D}\right)=\frac{6\text{.}0}{21\text{.}6}\times 100=27\text{.}8\approx 28\text{\%}$ (A) is obtained from the reaction of three equivalent \(1^{\circ} \mathrm{H}\) atoms. (B) is obtained from the reaction of two equivalent \(2^{\circ} \mathrm{H}\) atoms. (C) is obtained from the reaction of one equivalent \(3^{\circ} \mathrm{H}\) atoms. In the question: mention these 4 points A, B, C, D (D) is obtained from the reaction of six equivalent \(1^{\circ} \mathrm{H}\) atoms. .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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