Calculate the partial pressure exerted by dioxygen from a mixture of $32 \mathrm{~g} \mathrm{O}_2, 80…

Calculate the partial pressure exerted by dioxygen from a mixture of $32 \mathrm{~g} \mathrm{O}_2, 80 \mathrm{~g} \cdot \mathrm{Ar}$ (mol.mass 40) and 4 g dihydrogen( $\mathrm{P}_{\text {total }}=10 \mathrm{bar}$ ).
  1. 1 bar
  2. 2 bar
  3. 4 bar
  4. 5 bar

Solution

$\begin{aligned} & \mathrm{n}_{\mathrm{O}_2}=\frac{32}{32}=1 \mathrm{~mol} \\ & \mathrm{n}_{\mathrm{Ar}}=\frac{80}{40}=2 \mathrm{~mol} ; \mathrm{n}_{\mathrm{H}_2}=\frac{4}{2}=2 \mathrm{~mol} \\ & x_{\mathrm{O}_2}=\frac{\mathrm{n}_{\mathrm{O}_2}}{\mathrm{n}_{\mathrm{Total}}}=\frac{1}{1+2+2}=\frac{1}{5}=0.2 \\ & \mathrm{P}_{\mathrm{O}_2}=x_{\mathrm{O}_2} \times \mathrm{P}_{\text {Total }}=0.2 \times 10=2 \mathrm{bar}\end{aligned}$

Asked in: MHT CET 2024 (15 May Shift 1)

Practice more States of Matter questions on Aicharya