Calculate the number of atoms present in unit cell of an element having molar mass $190 \mathrm{~g} \mathrm{~mol}^{-1}$ and density $20 \mathrm{~g} \mathrm{~cm}^{-3}$. $\left[\mathrm{a}^3 \cdot \mathrm{N}_{\mathrm{A}}=38 \mathrm{~cm}^3 \mathrm{~mol}^{-1}\right]$

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Aicharya · Accepted Answer

Density $(ho)=\frac{M \mathrm{n}}{\mathrm{a}^3 \mathrm{~N}_{\mathrm{A}}}$ $\begin{aligned} & 20=\frac{190 	imes \mathrm{n}}{38} \ & \mathrm{n}=\frac{20 	imes 38}{190}=4 \end{aligned}$

Calculate the number of atoms present in unit cell of an element having molar mass $190 \mathrm{~g}…

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