Calculate the number of atoms in 0.3 gram metal if it forms bec structure $\left[\rho \times \mathrm{a}^3=3…
Calculate the number of atoms in 0.3 gram metal if it forms bec structure $\left[\rho \times \mathrm{a}^3=3 \times 10^{-22} \mathrm{~g}\right]$
$1.0 \times 10^{21}$
$2.0 \times 10^{21}$
$3.0 \times 10^{21}$
$4.0 \times 10^{21}$
Solution
For bec unit cell, $\mathrm{n}=2$.
No. of particles in $x \mathrm{~g}=\frac{x \mathrm{n}}{\rho \mathrm{a}^3}$
$\therefore \quad$ Number of atoms in 0.3 g of metal $=\frac{0.3 \times 2}{3 \times 10^{-22}}=2.0 \times 10^{21}$ atoms