Calculate the molar mass of an element with density $2.7 \mathrm{~g} \mathrm{~cm}^{-3}$ that forms fcc…

Calculate the molar mass of an element with density $2.7 \mathrm{~g} \mathrm{~cm}^{-3}$ that forms fcc structure. $\left[\mathrm{a}^3 \cdot \mathrm{N}_{\mathrm{A}}=40 \mathrm{~cm}^3 \mathrm{~mol}^{-1}\right]$
  1. $112 \mathrm{~g} \mathrm{~mol}^{-1}$
  2. $54 \mathrm{~g} \mathrm{~mol}^{-1}$
  3. $27 \mathrm{~g} \mathrm{~mol}^{-1}$
  4. $78 \mathrm{~g} \mathrm{~mol}^{-1}$

Solution

For fcc unit cell, $n=4$. $\begin{aligned} & \text { Density }(\rho)=\frac{M \text { n }}{a^3 N_A} \\ & 2.7=\frac{M \times 4}{40} \\ & M=\frac{2.7 \times 40}{4}=27 \mathrm{~g} \mathrm{~mol}^{-1} \end{aligned}$

Asked in: MHT CET 2023 (10 May Shift 1)

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