Calculate the magnetic moment of $\mathrm{Gd}^{3+}$ ion $(\mathrm{Z}=64)$.

Question

Aicharya · Accepted Answer

Gd $(64)=[\mathrm{Xe}] 4 f^{7} 5 d^{1} 6 s^{2}$
$\mathrm{Gd}^{3+}=[\mathrm{Xe}] 4 f^{7} 5 d^{0} 6 s^{0}$
i.e. no. of unpaired electrons $=7$
$\begin{aligned} \mu=& \sqrt{n(n+2)}=\sqrt{7(7+2)} \\ &=\sqrt{63}=7.93 \mathrm{BM} \end{aligned}$

Calculate the magnetic moment of $\mathrm{Gd}^{3+}$ ion $(\mathrm{Z}=64)$.

Solution