Calculate the fundamental frequency of a closed organ pipe of length 66.4 cm at 0°C, if the velocity of…
Calculate the fundamental frequency of a closed organ pipe of length 66.4 cm at 0°C, if the velocity of sound at 0°C is 332 ms -1.
Solution
Sol. Fundamental frequency of a closed organ pipe,
$f_1=\dfrac{v}{4L}=\dfrac{332}{4\times 66.4}\times 100=125\ \mathrm{Hz}$
Answer: $125 \mathrm{Hz}$
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