Calculate the edge length of unit cell that crystallises to form bcc structure. (Radius of atom is $2.17…
Calculate the edge length of unit cell that crystallises to form bcc structure. (Radius of atom is $2.17 \times 10^{-8} \mathrm{~cm}, \sqrt{3}=1.732$ )
$4.3 \times 10^{-8} \mathrm{~cm}$
$2.5 \times 10^{-8} \mathrm{~cm}$
$5.0 \times 10^{-8} \mathrm{~cm}$
$3.1 \times 10^{-8} \mathrm{~cm}$
Solution
For B.C.C unit cell
$\begin{aligned} & \sqrt{3} \mathrm{a}=4 \mathrm{r} \\ & \mathrm{a}=\frac{4 \times 2.17 \times 10^{-8}}{\sqrt{3}}=5.0 \times 10^{-8} \mathrm{~cm}\end{aligned}$