Calculate the coordination number of $\mathrm{Na}^{+}$in $\mathrm{NaCl}$ crystal, given radius of $\mathrm{Na}^{+}$and $\mathrm{Cl}^{-}$are $95 \mathrm{pm}$ and $181 \mathrm{pm}$ respectively.

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Aicharya · Accepted Answer

For $\mathrm{NaCl}$ crystal Radius ratio, $\frac{r_{\mathrm{Na}^{+}}}{r_{\mathrm{Cl}^{-}}}=\frac{95}{181}=0.5248$, which is, in the range of $0.414-0.732$. So, coordination number of $\mathrm{Na}^{+}$in $\mathrm{NaCl}$ crystal $=6$

Calculate the coordination number of \(\mathrm{Na}^{+}\)in \(\mathrm{NaCl}\) crystal, given radius of…

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