Calculate the concentration of $\mathrm{H}^{+}$ions in a solution if $\mathrm{pOH}$ is 11 .

Calculate the concentration of $\mathrm{H}^{+}$ions in a solution if $\mathrm{pOH}$ is 11 .
  1. $10^{-11} \mathrm{M}$
  2. $10^{-8} \mathrm{M}$
  3. $10^{-6} \mathrm{M}$
  4. $10^{-3} \mathrm{M}$

Solution

$\begin{array}{ll} & \mathrm{pOH}=11 \\ & \mathrm{pH}+\mathrm{pOH}=14 \\ \therefore \quad & \mathrm{pH}=14-\mathrm{pOH}=14-11=3 \\ & \mathrm{pH}=-\log _{10}\left[\mathrm{H}^{+}\right] \\ \therefore \quad & {\left[\mathrm{H}^{+}\right]=10^{-\mathrm{pH}^{-}}=10^{-3} \mathrm{M}}\end{array}$

Asked in: MHT CET 2023 (10 May Shift 1)

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