Calculate the cell constant of conductivity cell containing 0.1 M KCl solution having resistance $60 \Omega$…

Calculate the cell constant of conductivity cell containing 0.1 M KCl solution having resistance $60 \Omega$ and conductivity $0.014 \Omega^{-1} \mathrm{~cm}^{-1}$ at $25^{\circ} \mathrm{C}$.
  1. $0.42 \mathrm{~cm}^{-1}$
  2. $0.84 \mathrm{~cm}^{-1}$
  3. $0.60 \mathrm{~cm}^{-1}$
  4. $1.04 \mathrm{~cm}^{-1}$

Solution

$\begin{aligned} & \frac{1}{\text { Resistance }}=\text { cell constant } \times \text { conductivity } \\ & \therefore \quad \frac{1}{60 \Omega}=\mathrm{b} \times 0.014 \Omega^{-1} \mathrm{~cm}^{-1} \\ & \therefore \quad \mathrm{~b}=0.84 \mathrm{~cm}^{-1}\end{aligned}$

Asked in: MHT CET 2024 (16 May Shift 2)

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