Calculate the amount of solute dissolved in $3 \mathrm{dm}^3$ water having osmotic pressure $0.3…
Calculate the amount of solute dissolved in $3 \mathrm{dm}^3$ water having osmotic pressure $0.3 \mathrm{~atm}$ at $300 \mathrm{~K}$
(Molar mass of solute $=108 \mathrm{~g} \mathrm{~mol}^{-1}, R=0.0821 \mathrm{~atm} \mathrm{dm}^3 \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )
4.51 gram
3.95 gram
3.45 gram
5.26 gram
Solution
Osmotic pressure
$\begin{aligned} & \pi=i C R T \\ & 0.3=1 \times \frac{W}{108} \times \frac{1}{3} \times 0.0821 \times 300 \\ & W=3.95 \mathrm{gm}\end{aligned}$