Calculate the amount of solute dissolved in 612 grams of water at $30^{\circ} \mathrm{C}$ if molar mass of…

Calculate the amount of solute dissolved in 612 grams of water at $30^{\circ} \mathrm{C}$ if molar mass of solute is $342 \mathrm{~g} \mathrm{~mol}^{-1}$ (Relative vapour pressure lowering is 0.025 and molar mass of water $18 \mathrm{~g} \mathrm{~mol}^{-1}$ )
  1. 142.5 gram
  2. 270.6 gram
  3. 240.2 gram
  4. 290.7 gram

Solution

$\frac{\Delta P}{P_A^{\circ}}=x_B \simeq \frac{n_B}{n_A}$ $\frac{W_B}{342} \times \frac{18}{612}=0.025$ $W_B=290.7$

Asked in: MHT CET 2022 (08 Aug Shift 2)

Practice more Solutions questions on Aicharya