Calculate the amount of solute dissolved in 160 gram solvent that boils at $85^{\circ} \mathrm{C}$. the…

Calculate the amount of solute dissolved in 160 gram solvent that boils at $85^{\circ} \mathrm{C}$. the molar mass of solute is $120 \mathrm{~g} \mathrm{~mol}^{-1}$. $\left(\mathrm{K}_{\mathrm{b}}\right.$ for solvent $=2.7^{\circ} \mathrm{C} \mathrm{kg} \mathrm{mol}^{-1}$ and boiling point of solvent $\left.=76^{\circ} \mathrm{C}\right)$
  1. 64 gram
  2. 42 gram
  3. 50 gram
  4. 60 gram

Solution

$\Delta \mathrm{T}_{\mathrm{b}}=(85-76)=2.7 \times \frac{\mathrm{W}_{\mathrm{B}}}{120} \times \frac{1000}{160}$ $\mathrm{W}_{\mathrm{B}}=64 \mathrm{~g}$

Asked in: MHT CET 2022 (10 Aug Shift 2)

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