Calculate radius of fourth orbit of $\mathrm{B}^{4+}$ ion.

Question

Aicharya · Accepted Answer

$\mathrm{r}_{\mathrm{n}}=\frac{52.9(\mathrm{n})^2}{\mathrm{Z}} \mathrm{pm}$ $\mathrm{B}^{4+}$ is a hydrogen-like species having $\mathrm{Z}=5$. Radius of the fourth orbit of $\mathrm{B}^{4+}$ $\begin{aligned} & =\mathrm{r}_4=\frac{52.9 	imes(4)^2}{5} \mathrm{pm} \ & =169.3 \mathrm{pm} \end{aligned}$

Calculate radius of fourth orbit of $\mathrm{B}^{4+}$ ion.

Solution