Calculate pH of 0.002 M KOH solution.

Calculate pH of 0.002 M KOH solution.
  1. 10.4
  2. 11.3
  3. 12.4
  4. 13.2

Solution

$\begin{aligned} & \mathrm{pOH}=-\log _{10}\left[\mathrm{OH}^{-}\right] \\ & \because \quad \mathrm{pOH}=-\log _{10}[0.002]=2.69 \\ & \because \quad \mathrm{pH}+\mathrm{pOH}=14 \\ & \mathrm{pH}=14-\mathrm{pOH}=14-2.69=11.3\end{aligned}$

Asked in: MHT CET 2024 (03 May Shift 2)

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