Calculate osmotic pressure of 0.1 M aqueous solution of an electrolyte at 300 K if van't Hoff factor is $1…
- 2.15 atm
- 2.41 atm
- 2.77 atm
- 3.25 atm
Solution
The osmotic pressure $\pi$ of an electrolyte solution is given by $\pi = iCRT$, where $i = 1.125$ is the van't Hoff factor, $C = 0.1 \text{ M}$ is the molar concentration, $R = 0.0821 \text{ atm dm}^3 \text{ K}^{-1} \text{ mol}^{-1}$ is the gas constant, and $T = 300 \text{ K}$ is the temperature.
Substitution yields $\pi = 1.125 \times 0.1 \times 0.0821 \times 300 = 2.770875 \text{ atm}$.
Rounding to two decimal places, $\pi \approx 2.77 \text{ atm}$, which corresponds to option $\boxed{\text{C}}$.
Asked in: MHT CET 2025 (05 May Shift 2)