Calculate number of moles present in $9.10 imes 10^{-2} \mathrm{~kg}$ of water.

Question

Calculate number of moles present in $9.10 	imes 10^{-2} \mathrm{~kg}$ of water.

Aicharya · Accepted Answer

Molar mass of water $\left(\mathrm{H}_2 \mathrm{O}ight)=18 	imes 10^{-3} \mathrm{~kg} \mathrm{~mol}^{-1}$ $	herefore \quad$ Moles of $\mathrm{H}_2 \mathrm{O}=\frac{9.10 	imes 10^{-2}}{18 	imes 10^{-3}}=5.05 \approx 5.0 \mathrm{~mol}$

Calculate number of moles present in $9.10 \times 10^{-2} \mathrm{~kg}$ of water.

Solution