Calculate $\left[\mathrm{H}_3 \mathrm{O}^{+}\right]$in 0.02 M solution of monobasic acid if dissociation…
Calculate $\left[\mathrm{H}_3 \mathrm{O}^{+}\right]$in 0.02 M solution of monobasic acid if dissociation constant is $1.8 \times 10^{-5}$.
- $\quad 3.0 \times 10^{-4} \mathrm{M}$
- $6.0 \times 10^{-4} \mathrm{M}$
- $2.0 \times 10^{-4} \mathrm{M}$
- $4.0 \times 10^{-4} \mathrm{M}$
Solution
For a weak monobasic acid,
$\begin{aligned}
\therefore \quad & \alpha=\sqrt{\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{c}}}=\sqrt{\frac{1.8 \times 10^{-5}}{0.02}}=3 \times 10^{-2} \\
& {\left[\mathrm{H}_3 \mathrm{O}^{+}\right]=\alpha \mathrm{c}=3 \times 10^{-2} \times 0.02=6.0 \times 10^{-4} \mathrm{M} }
\end{aligned}$
Asked in: MHT CET 2024 (03 May Shift 1)
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