Calculate freezing point of a 0.05 molal aqueous solution of a nonelectrolyte?
Calculate freezing point of a 0.05 molal aqueous solution of a nonelectrolyte?
- 186 K
- 272.9 K
- 93 K
- 278 K
Solution
$\begin{aligned}
\Delta T_f & =K_f \times m \\
& =1.86 \times 0.02 \\
& =0.093 \mathrm{~K}
\end{aligned}$
or $T_f-T=0.093$
$\begin{aligned}
T & =273-0.093 \\
& =272.9 \mathrm{~K}
\end{aligned}$
Asked in: MHT CET 2022 (08 Aug Shift 1)
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