Calculate change in internal energy if \(\Delta H=-92.2 \mathrm{~kJ}, P=40 \mathrm{~atm}\) and \(\Delta V=-1…
Calculate change in internal energy if \(\Delta H=-92.2 \mathrm{~kJ}, P=40 \mathrm{~atm}\) and \(\Delta V=-1 \mathrm{~L}\).
- \(-42 \mathrm{~kJ}\)
- \(-88 \mathrm{~kJ}\)
- \(+88 \mathrm{~kJ}\)
- \(+42 \mathrm{~kJ}\).
Solution
\(\Delta H=\Delta E+P \Delta V\)
\(\begin{aligned}
\Delta E & =\Delta H-P \Delta V=-92.2-40 \times(-1) \times 101 \times 10^{-3} \\
& =-92.2+4.04=-88.16 \mathrm{~kJ} \approx-88 \mathrm{~kJ} .
\end{aligned}\)
Asked in: NEET 2010 (Screening)
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