Chemistry › s Block Elements › Alkaline Earth Metals
Calcium phosphide reacts with water to form $\mathrm{Ca}(\mathrm{OH})_2$ and $X$. When $X$ is passed into…
Calcium phosphide reacts with water to form $\mathrm{Ca}(\mathrm{OH})_2$ and $X$. When $X$ is passed into $\mathrm{CuSO}_4$ solution. $Y$ and $\mathrm{H}_2 \mathrm{SO}_4$ are formed. What is $Y$ ?
$\left[\mathrm{Cu}\left(\mathrm{PH}_3\right)_4\right]^{2 *}$ $\left[\mathrm{Cu}\left(\mathrm{PH}_3\right)_6\right]^{2+}$ $\mathrm{Cu}_3 \mathrm{P}_2$ $\mathrm{CuHPO}_4$ Solution
Calcium phosphide reacts with water to form calcium hydroxide and phosphine.
$
\begin{aligned}
& \mathrm{Ca}_3 \mathrm{P}_2+6 \mathrm{H}_2 \mathrm{O} \longrightarrow 3 \mathrm{Ca}(\mathrm{OH})_2 a q+2 \mathrm{PH}_3(g) \\
& \text { Calcium Water Calcium hydroxide Phosphine } \\
& \text { Phosphide } \\
&
\end{aligned}
$
Phosphine when passed into $\mathrm{CuSO}_4$ solution, it reacts to produce black precipitate of cupric phosphide and $\mathrm{H}_2 \mathrm{SO}_4$.
$
\begin{aligned}
& 3 \mathrm{PH}_3+3 \mathrm{CuSO}_4 \longrightarrow \mathrm{Cu}_3 \mathrm{P}_2 \\
& \text { Phosphine Copper sulphate Cupric phosphide } \\
& +3 \mathrm{H}_2 \mathrm{SO}_4 \\& \text { Sulphuric acid }\\
&
\end{aligned}
$
Asked in: AP EAMCET 2018 (23 Apr Shift 2)
Practice more s Block Elements questions on Aicharya