\(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br} \underset{\mathrm{AgCN}}{\longrightarrow} \mathrm{Xn}…
\(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br} \underset{\mathrm{AgCN}}{\longrightarrow} \mathrm{Xn} \underset{\mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}}{\stackrel{\text { Reduction }}{\longrightarrow}} \mathrm{Y}\), Here $\mathrm{Y}$ is
- Ethyl methyl amine
- $\mathrm{n}$ -propylamine
- Isopropylamine
- Ethylamine
Asked in: JEE-TOPICTESTS-CHEMISTRY
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