By what factor does the average velocity of a gaseous molecule increase when the temperature (in Kelvin) is…
By what factor does the average velocity of a gaseous molecule increase when the temperature (in Kelvin) is doubled?
- 2.8
- 4.0
- 1.4
- 2.0
Solution
Average velocity $=\sqrt{\frac{8 R T}{\pi M}}$
$\begin{aligned}
& \therefore V_{a v} \propto \sqrt{T} \\
& \text { or } \frac{\left(V_{a v}\right)_2}{\left(V_{a v}\right)_1}=\sqrt{\frac{2 T}{T}}=1.4
\end{aligned}$
Asked in: NEET 2011 (Screening)
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