By simplifying $i^{18}-3 i^7+i^2\left(1+i^4\right)(i)^{22}$, we get

Question

Aicharya · Accepted Answer

$i^{18}-3 i^7+i^2\left(1+i^4ight)(i)^{22}$ $=i^{4 	imes 4+2}-3 i^{4+3}+-1(1+1)\left(i^2ight)^{11}$ $=i^2-3 i^3+2 \quad\left[\because i^2=-1ight.$ and $\left.i^4=1ight]$ $=-1+3 i+2=1+3 i$

By simplifying $i^{18}-3 i^7+i^2\left(1+i^4\right)(i)^{22}$, we get

Solution