By Remainder theorem, when $p(x) = x^{2} - 4x + 7$ is divided by $(x - 1)$, the remainder is

By Remainder theorem, when $p(x) = x^{2} - 4x + 7$ is divided by $(x - 1)$, the remainder is
  1. $4$
  2. $0$
  3. $7$
  4. $-4$

Solution

$p(1) = 1 - 4 + 7 = 4$.

Asked in: MH-SSC-9

Practice more Polynomials questions on Aicharya